IMDb > Lana Kane (Character)
Lana Kane
Quicklinks
Top Links
main detailsbiographyby votesphoto galleryquotes
Filmographies
by yearby typeby ratingsby votesby TV seriesby genreby keyword
Biographical
biography
Did You Know?
photo galleryquotes

Lana Kane (Character)
from "Archer" (2009)

The content of this page was created by users. It has not been screened or verified by IMDb staff.
Photos (See all 10 | slideshow) Related Videos (see all 63)
Archer: Season 7: Episode 10 -- Things get even deadlier on the set of Deadly Velvet when someone turns up, you guessed it, dead.

Edit Photos

There may be more photos available for this character. To select more photos to be displayed in this character's gallery, click the Edit Photos link.


Overview

Biography:
Lana Kane (Aisha Tyler) Lana Kane is a top... See more »

Filmography

   Edit Credits
There may be more credits available for this character. To edit the credits displayed or to add more credits to this character's filmography, click the Edit Credits link.


  1. "Archer"
    ... aka "Archer Vice" - USA (fifth season title)
        - Deadly Velvet: Part 2 (2016) TV episode, Played by Aisha Tyler
        - Deadly Velvet: Part 1 (2016) TV episode, Played by Aisha Tyler
        - Liquid Lunch (2016) TV episode, Played by Aisha Tyler
        - Double Indecency (2016) TV episode, Played by Aisha Tyler
        - Bel Panto: Part II (2016) TV episode, Played by Aisha Tyler
          (81 more)

Additional Details

Genres:

Fun Stuff

Quotes:
From "Archer: El Secuestro (#2.10)" (2011)
Lana Kane: Kinda curious. Why do you even work at ISIS?
Cheryl Tunt: Why do you?
Lana Kane: Ha! Because I'm not worth a billion dollars.
Cheryl Tunt: Yeah, me neither. I have to split it with my stupid brother, Cecil.
Malory Archer: And how much will you be splitting?
Cheryl Tunt: It actually is a billion dollars.
Lana Kane: I am literally wet with jealousy.
See more »

You may correct errors and omissions on this page directly. Clicking the 'Update' button will take you through a step-by-step process.